SLAB THICKNESS                                       = 6.5 inch = 0.542 ft
EFFECTIVE DEPTH                                     = 6.5 – 0.75=
5.75 inch
FLOOR FINISH                                             =
25 psf
SELF-WEIGHT OF SLAB                            = 0.542 x150 pcf =
81.3 psf
TOTAL DEAD LOAD                                   = 106.3 psf
LIVE LOAD                                                   =
42 psf
FACTORED LOAD (1.4DL+1.7LL)            = (1.4 x 106.3 + 1.7 x 42) = 220.22
psf
STEP- 1: DETERMINATION OF
PUNCHING LOAD
            
            Total Area                                           =
19 ft 11 inch X 20 ft = 398.33 sft
            Punching Area                                    =
(18+5.75) X (18+5.75) inch = 3.92 sft
`           Effective Area                                     =
398.33 – 4.17 = 394.41 sft
            Developed Punching Load, Vu              = 394.41 x 220.22 = 86856.97 lb = 86.9 lb
STEP- 2: DETERMINATION OF
ALLOWABLE PUNCHING LOAD
            
            Allowable Punching Load, ɸVc             = ɸ4Æ›b0d
            Reduction Factor, ɸ                            =
0.85 (BNBC 2006 Table- 6.6.1)
            Modification Factor, Æ›                        =
1 (Normal Weight Concrete)
            Punching Perimeter, b0                       = 4 x (18+5.75) =95 inch
            Effective Depth, d                              =
6.5 – 0.75= 5.75 inch
            Concrete Strength, 
                Allowable
Punching Load, ɸVc             =
(0.85 x 4 x 1 x 95 x 5.75 x 
SO, WE CAN CONCLUDE THAT FLAT SLAB OF
THIS BUILDING IS ADEQUATE FOR PUNCHING SHEAR.
 
 
 
 
 
 
 
 
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